35x^2+28x+17=17

Solution for 35x^2+28x+17=17 equation:

35x^2+28x+17=17

We move all terms to the left:

35x^2+28x+17-(17)=0

We add all the numbers together, and all the variables

35x^2+28x=0

a = 35; b = 28; c = 0;
Δ = b2-4ac
Δ = 282-4·35·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-28}{2*35}=\frac{-56}{70}
=-4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+28}{2*35}=\frac{0}{70}
=0
$